THERMODYNAMIC PROCESS OF PERFECT GAS - Mechanical2020Diploma.Blogspot.Com

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Sunday, August 2, 2020

THERMODYNAMIC PROCESS OF PERFECT GAS

THERMODYNAMIC PROCESS OF PERFECT GAS: -

  1. CONSTANT VOLUME PROCESS / ISOCHORIC PROCESS: - [n = ∞ ]

Follows Law – Gay-Lussac Law

P ∝ T (When V = Constant)

Heat Transferred Q1-2 = (U2 – U1) = mCv (T2 –T1)

Work Done dW = 0

Entropy Change dS = Cvln (T2 / T1)

 

  1. CONSTANT PRESSURE PROCESS / ISOBARIC PROCESS: - [n = 0]

Follows Law – Charles’ Law

V ∝ T (When P = Constant)

Heat Transferred Q1-2 = mCp (T2 –T1)

Work Done dW = P (V2 – V1)

                              = mR (T2 –T1)

Internal energy dE = dQ – dW

                              =mCp (T2 –T1) – mR (T2 –T1)

                              = mCp (T2 –T1) – m (Cp – Cv) (T2 –T1)

                              = m Cv (T2 – T1)

Entropy Change dS = Cvln (T2 / T1)


3. CONSTANT TEMPERATURE PROCESS / ISOTHERMAL PROCESS: -[n = 1]

Follows Law – Boyel’s Law

P ∝ 1 / V (When T = Constant)

PV = CONSTANT.

Internal energy (dE) = 0

Isothermal Process
Fig.1 | Isothermal Process

dQ = dE + dW

= dW      [dE = 0]

= P. dV

  1. P1V1 = PV

    P = P 1V1 / V 

    = (P1V1 / V). dV


    = P1V1 ln(V2/V1)

     

    Heat Transferred dQ = dW = P1V1 ln(V2/V1) OR P1V1 ln(P2 / P1)

    Entropy Change dS = R ln(V2/V1)


4. ADIABATIC PROCESS OR ISENTROPIC PROCESS: - [n =γ ]

Follows Law

PVγ = CONSTANT.

Heat Transferred dQ = 0

Internal energy (dE) = - dW

dW = P. dV

    = (P1V1γ / Vγ).dV

Adiabatic Process
Fig.2 | Adiabatic process




Entropy Changes dS = 0


5. POLYTROPIC PROCESS: - [n =γ ]

Follows Law

PVn = CONSTANT.

Heat Transferred Q1-2 = Cn (T2 – T1)

                                             = Cv (γ – n/ γ – 1) (T2 - T1)

                                             = (γ – n/ γ – 1) X Work Done

 

Work Done (W1-2) = (P1V1 – P2V2) / n-1

Internal energy (dE) = mCv (T2 - T1

Entropy Change dS =  











  • FREE EXPANSION PROCESS: - When a fluid is allowed to expand suddenly in to a vacuum chamber through an orifice of  large dimension.
 Q1-2 = 0 ;      W1-2 = 0 ;    & dU = 0 

  • THROTTLING PROCESS: - When a perfect gas is expanded through aperture of minute dimension (Slightly open valve)
Enthalpy remains constant.

 Q1-2 = 0 ;      W1-2 = 0 ;    & dU = 0 






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